In his pocket a boy has 3 red marbles 4 blue marbles and 4 green marbles.
In his pocket a boy has 3 red marbles 4 blue marbles and 4 green.
While it is possible to reach into his pocket and pull out 3 marbles one of each color at the same time it is not likely but possible that they would all be all blue with this in mind he needs to pull at least 2 more marbles to possibly get one of each remaining colors.
Answer by edwin mccravy 17924 show source.
9 picks required to assure at least one of each color.
The next marble must be green and he will at least one of each color.
Algebra customizable word problem solvers age solution.
How many will he have to take out of his packet to ensure that he has one of each color what might happen.
A boy has 4 red marbles and 5 green marbles in his left pocket and 5 red marbles and 3 green marbles in his right pocket.
Pick 4 green pick 4 blue next pick will give and red and you will have one of each color ans.
Answer by checkley75 3666 show source.
But the same situation could occur.
Therefore the number of marbles to be removed to ensure success would be 11 3 1 9.
How many will he have to take out of his packet to ensure that he has one of each color.
In his pocket a boy has 3 red marbles 4 blue marbles and 4 green marbles.
How many will he have to take out of his packet to ensure that he has one of each color he could pick 3 red then 4 blue.
In his pocket a boy has 3 red marbles 4 blue marbles and 4 green marbles.
In his pocket a boy has 3 red marbles 4 blue marbles and 4 green marbles.
Afterwards he drew a marble at random from his right pocket.
A boy has 3 red marble in his pocket 4 blue marbles and 4 green marbles.
A boy has 3 red marble in his pocket 4 blue marbles and 4 green marbles.
Of picks 3 4 1 8 cheers stan h.
He might pull out two of the same color say 2 green.
A boy has 3 red marbles in his pocket 4 blue marbles and 4 green marbles.
What is the probability that the marble was red.
How many will he have to take out of his pocket to ensure he has taken out atleast one of every color.
He will have to take out a number equal to the sum of all the marbles less the number of marbles in the smallest group of colored marbles plus one marble.